在实际中遇到一个时间处理问题,需要将 Sep 06, 2014 19:30 (UTC 时间) 和 当前时间比较早晚,知道 此 2014-09-06 19:30 格式时间的运算。因此,在处理时,就想
先将sep 格式时间转化成 后面一个格式的时间样子,没有找到相关函数,于是自己简单的写了个程序,仅记于此,以备查询
代码如下:
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# -*- coding: utf-8 -*- from datetime import date from datetime import datetime from datetime import timedelta # # #如果是返回当前时间,可以简单的写成 # # time.localtime() # # #这个返回UTC时间 # # time.gmtime() # lt = time.localtime() # tm = time.gmtime() # ft = time.strftime('%Y-%m-%d %H-%M',lt) # ft2 = time.strftime('%Y-%m-%d %H:%M',tm) # print ft, ft2 # print '--------------------------------------------------------' # now = datetime.datetime.now() # now = now.replace(day = 1) # print now # print now.time() # # mytime = ['2014-09-06 20:19'] # #mytime2 = '2014-10-09 14:32' # str = "".join(mytime) # print str # retime = datetime.strptime(str,'%Y-%m-%d %H:%M') # print retime # retime = retime +timedelta(hours = 8) # print retime # # tdtime = datetime.now() # print tdtime # if retime <= tdtime - timedelta(days = 7): # print "too early" # # #Sep 06, 2014 19:30 monthdic = { 'Jan' : '01' , 'Feb' : '02' , 'Mar' : '03' , 'Apr' : '04' , 'May' : '05' , 'Jun' : '06' , 'Jul' : '07' , 'Aug' : '08' , 'Sep' : '09' , 'Oct' : '10' , 'Nov' : '11' , 'Dec' : '12' } def time_format(timestr): timestr = timestr.replace( ',' ,'') #print timestr timelist = timestr.split() #print timelist mon = "".join(timelist[ 0 ]) #print mon timelist[ 0 ] = monthdic[mon] #print timelist mytime = " ".join(timelist[2])+'-'+" ".join(timelist[0])+'-'+" ".join(timelist[1])+' '+ " ".join(timelist[ 3 ]) return mytime if __name__ = = '__main__' : timestr = 'Sep 06, 2014 19:30' str = time_format(timestr) print str mytime = datetime.strptime( str , '%Y-%m-%d %H:%M' ) print mytime mytime = mytime + timedelta(hours = 8 ) print mytime tdtime = datetime.now() print tdtime if mytime < = tdtime - timedelta(days = 7 ): print "too early" |
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